Now this Petrol Pump puzzle is definitely one of those sets that are meant only for the experienced and the most skilled. This is because of its complexity owing to the 3x2 grid formation and various conditions. However that should not deter you from trying this. What more? the puzzle is solved systematicaly by Rajesh (4 time CAT 100 %iler) in the video solution available here. The best place to gain experience is undoubtedly the CAT previous year paper and do not forget to include it to your online preparation for CAT. Now try this question yourself before looking at the video solution.
Fuel contamination levels at each of 20 petrol pumps P1, P2, …, P20 were recorded as either high, medium, or low.
1. Contamination levels at three pumps among P1 – P5 were recorded as high.
2. P6 was the only pump among P1 – P10 where the contamination level was recorded as low.
3. P7 and P8 were the only two consecutively numbered pumps where the same levels of contamination were recorded.
4. High contamination levels were not recorded at any of the pumps P16 – P20.
5. The number of pumps where high contamination levels were recorded was twice the number of pumps where low contamination levels were recorded.
Question 1 : Which of the following MUST be true?
We know that three of P1 to P5 are recorded as High. This means the other two should be M. So, let us fill this data in.
P7 and P8 are both same, so both could be H or both M. Let us try both. We put P7 and P8 in, P9 and P10 get filled automatically.
Let us fill in the totals as well.
The number of pumps where high contamination levels were recorded was twice the number of pumps where low contamination levels were recorded.
So, of the number of low contaminations were x, then the number of high contaminations would be 2x.
H + L = 3x {3, 6, 9, 12, 15, or 18} or, M should be from {2, 5, 8, 11, 14, 17}
L + H is at least 5 so M cannot be 14 or 17. M cannot be 2 either. So, we can have M to be 5, 8 or 11.
So, we can have H, M, L to be {10, 5, 5} or {8, 8, 4} or {6, 11, 3}
There is no H in the P16 to P20 range, so total H cannot be 10. So, H, M, L being {10, 5, 5} can be ruled out.
So, we can have H, M, L to be {8, 8, 4} or {6, 11, 3}.
We cannot have more than 5 M’s in the range from P16 to P20.
So, we now know that {6, 11, 3} is also ruled out. So H, M, L has to be {8, 8, 4}.
We know that in the first 10 pipes we could have has H, M, L could have been {6, 3, 1} or {4, 5, 1}
So, H, M, L for the last 10 should be {2, 5, 3} or {4, 3, 3}. Since there is no H in the first 5 pipes, we cannot have 4 H in the P16 to P20 range.
So, we need to have only {6, 3, 1} in the first range.
The last 10 pipes should have H, M, L to be {2, 5, 3}.
High contamination levels were not recorded at any of the pumps P16 – P20. So, the last 5 should be either MLMLM or LMLML.
If the last 5 were LMLML, then we would not have one more L for P11 to P15. So, P11 to P15 should be MHMHM. Now, let us fine-tune this.
We know that P11 cannot be H otherwise P10- and P11 would be H.
So, we need to accommodate 2 H’s in the P12 to P15 range.
We could have them at P12 and P14, P12 and P15 and P13 and P15.
If P15 were not H, it has to be L. So, we can fill the first column completely.
P12 need not have been high. Choice A need not be true.
P20 could have been L, so Choice B is also out.
P10 was high. This is indeed true.
P13 need not have been low.
Choice C is true.
The question is "Which of the following MUST be true?"
Choice C is the correct answer.
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