CAT 2018 Question Paper | Quants Slot 2
CAT Previous Year Paper | CAT Number theory and Inequalities Questions | Question 13
CAT Questions Here's a question from CAT Previous Year Papers 2018 that appears simple, but requires a strong predisposition for math! If you can prove your metal by eliminating the wrong options from this CAT 2018 Question Paper problem, then you are through! Try your hands on this beauty from Inequalities and then go on to have a look at how Rajesh solves it.
Question 13 : The smallest integer n for which 4n ＞ 1719 holds, is closest to
- 33
- 39
- 37
- 35
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Explanatory Answer
Method of solving this CAT Question from Number theory and Inequalities
Given that 4n > 1719
The smallest integer n for which 4n > 1719 holds has to be found 4n > 1719 can be also written as (42)\\frac{n}{2}) > 1719
16\\frac{n}{2}) > 1719
We can assume n = 19, 1619 cannot be greater than 1719
16\\frac{38}{2}) cannot be greater than 1719 so n cannot be 38
And similarly n cannot be less than 38 so we can eliminate the options less than 38 and so the only possible value n could take is 39
The question is "The smallest integer n for which 4n ＞ 1719 holds, is closest to"
Hence, the answer is 39
Choice B is the correct answer.
