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CAT Previous Year Paper | CAT Number theory and Inequalities Questions | Question 13

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Question 13 : The smallest integer n for which 4n > 1719 holds, is closest to

  1. 33
  2. 39
  3. 37
  4. 35

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Explanatory Answer

Method of solving this CAT Question from Number theory and Inequalities

Given that 4n > 1719
The smallest integer n for which 4n > 1719 holds has to be found 4n > 1719 can be also written as (42)\\frac{n}{2}) > 1719
16\\frac{n}{2}) > 1719
We can assume n = 19, 1619 cannot be greater than 1719
16\\frac{38}{2}) cannot be greater than 1719 so n cannot be 38
And similarly n cannot be less than 38 so we can eliminate the options less than 38 and so the only possible value n could take is 39

The question is "The smallest integer n for which 4n > 1719 holds, is closest to"

Hence, the answer is 39

Choice B is the correct answer.

 

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