A delightful question from time and distance. This question can be solved in less than 1 minute if you have a strong foundation in the topic. Going the algebraic & formulaic approach will prove to be a time guzzler. This question illustrates why having a good basics is more important by hearting formulas as part of your **CAT online preparation**.

Question 19 : In a race of three horses, the first beat the second by 11 metres and the third by 90 metres. If the second beat the third by 80 metres, what was the length, in metres, of the racecourse? [TITA]

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A beats B by 11 meters. When B completes the 11 meters, there is a lead of 80 meters to C

So, C must have travelled only 90 - 80 = 10 meters

When B travels 11 meters, C travels only 10 meters

Ratio of distance travelled by second and third horse are11x and 10 x respectively

We know that the second horse beats the third horse by 80 meters.

So, Length of the track = Distance travelled by the second horse = 11 x 80 = 880 meters

The question is **"In a race of three horses, the first beat the second by 11 metres and the third by 90 metres. If the second beat the third by 80 metres, what was the length, in metres, of the racecourse? [TITA] " **

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