CAT 2022 Question Paper | DILR Slot 3

CAT Previous Year Paper | CAT DILR Questions | Question 2

CAT 2022 DILR saw a change in patter. Unlike the previous years, all the four sets had 5 questions this year. There were 6 TITA Qs this year. Atleast two sets were doable in each slot and one of the four sets was extremely tough. Choice of Sets became a crucial factor. Overall this section was at a medium to high level of difficulty.

All the first-year students in the computer science (CS) department in a university take both the courses (i) AI and (ii) ML. Students from other departments (non-CS students) can also take one of these two courses, but not both. Students who fail in a course get an F grade; others pass and are awarded A or B or C grades depending on their performance. The following are some additional facts about the number of students who took these two courses this year and the grades they obtained.

1. The numbers of non-CS students who took AI and ML were in the ratio 2 : 5.
2. The number of non-CS students who took either AI or ML was equal to the number of CS students.
3. The numbers of non-CS students who failed in the two courses were the same and their total is equal to the number of CS students who got a C grade in ML.
4. In both the courses, 50% of the students who passed got a B grade. But, while the numbers of students who got A and C grades were the same for AI, they were in the ratio 3 : 2 for ML.
5. No CS student failed in AI, while no non-CS student got an A grade in AI.
6. The numbers of CS students who got A, B and C grades respectively in AI were in the ratio 3 : 5 : 2, while in ML the ratio was 4 : 5 : 2.
7. The ratio of the total number of non-CS students failing in one of the two courses to the number of CS students failing in one of the two courses was 3 : 1.
8. 30 students failed in ML.

Question 2 : How many CS students failed in ML?


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Explanatory Answer

Set 1

The numbers of non-CS students who took AI and ML were in the ratio 2 : 5.
The number of non-CS students who took either AI or ML was equal to the number of CS students.
The numbers of non-CS students who failed in the two courses were the same and their total is equal to the number of CS students who got a C grade in ML.
Set 1

No CS student failed in AI, while no non-CS student got an A grade in AI.
The numbers of CS students who got A, B and C grades respectively in AI were in the ratio 3 : 5 : 2, while in ML the ratio was 4 : 5 : 2.
Set 1

The ratio of the total number of non-CS students failing in one of the two courses to the number of CS students failing in one of the two courses was 3 : 1.
Set 1

30 students failed in ML. \(y+\frac{2y}{3}\). y = 18.
Total number of students in CS = 210. So, non-CS AI = 60; non-CS ML = 150
Now, we can find K.
Set 1

In both the courses, 50% of the students who passed got a B grade. But, while the numbers of students who got A and C grades were the same for AI, they were in the ratio 3 : 2 for ML.

Number of B grades in AI = 252/2 = 126
Number of B grades in ML = 330/2 = 165
Number of C grades in AI = 63.
So, C grades in AI for non-CS = 21.

Total number of candidates who cleared ML = 330.
Of this 165 for B, A + C = 165. Split in the ratio 3 : 2 = 99 : 66
Set 1


The question is " How many CS students failed in ML? "

Hence, the answer is '12'

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