CAT 2024 Quant was dominated by Algebra followed by Arithmetic. In Arithmetic, the questions were dominated by topics like Speed-time-distance, Mixture and Alligations. This year, there was a surprise. The questions from Geometry were relatively on the lower side as compared to the previous years. There were 8 TITA Qs this year. Overall this section was at a medium level of difficulty.
Question 6 If \(10^{68}\) is divided by 13 , the remainder is
\[
\begin{array}{lll}
\operatorname{Re}\left[\frac{10^1}{13}\right]=10 ; &
\operatorname{Re}\left[\frac{10^2}{13}\right]=9 ; &
\operatorname{Re}\left[\frac{10^3}{13}\right]=12 ; \\
\operatorname{Re}\left[\frac{10^4}{13}\right]=3 ; &
\operatorname{Re}\left[\frac{10^5}{13}\right]=4 ; &
\operatorname{Re}\left[\frac{10^6}{13}\right]=1
\end{array}
\]
So, after every power of 6, the remainder repeats its patterns.
Hence,
\[
\begin{array}{l}
\operatorname{Re}\left[\frac{10^{66}}{13}\right]=1 \\
\operatorname{Re}\left[\frac{10^{67}}{13}\right]=10 \\
\operatorname{Re}\left[\frac{10^{68}}{13}\right]=9
\end{array}
\]
The question is "If \(10^{68}\) is divided by 13 , the remainder is "
Choice B is the correct answer.
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