# IPM Sample Paper 2020 | IPM Rohtak Quantitative Aptitude

###### IPMAT Sample Paper | IPMAT Question Paper | Question 36

IPMAT 2020 Sample Paper IPM Rohtak Quantitative Aptitude. Solve questions from IPMAT 2020 Sample Paper from IPM Rohtak and check the solutions to get adequate practice. The best way to ace IPMAT is by solving IPMAT Question Paper. To solve other IPMAT Sample papers, go here: IPM Sample Paper

Question 36 : A boatman goes 2 km against the current of the stream in 1 hour and goes 1 km along the current in 10 minutes. How long will it take to go 5 km in stationary water?

1. 40 minutes
2. 1 hour
3. 1 hr 15 min
4. 1 hr 30 min

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Let the speed of the boat in still water be ‘b’.
And the speed of the stream be ‘s’.

It is given that the boatman goes 2 km against the current of the stream in 1 hour.
Which means the upstream speed = 2/1 = 2kmph.
Upstream speed = b – s = 2 kmph.

Also it is given that he goes 1 km along the current in 10 minutes.
Which means the downstream speed = 1/(10/60) = 6 kmph.
Downstream speed = b + s = 6kmph.

b – s = 2kmph
b + s = 6 kmph

b – s + b + s = 2 + 6 = 8kmph
2b = 8 kmph

b = 4kmph.

The speed of the boat in still water = 4 kmph.

Time taken to travel 5 km = 5/4 hours = 1 ¼ hours. (Speed = Distance / Time taken)
= 1 hour 15 minutes

Therefore, time taken by the boat to travel 5km in still water = 1 hour 15 minutes.

The question is "A boatman goes 2 km against the current of the stream in 1 hour and goes 1 km along the current in 10 minutes. How long will it take to go 5 km in stationary water?"

##### Hence, the answer is 1 hr 15 min

Choice C is the correct answer

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