# CAT 2018 Question Paper | CAT LR DI

###### CAT Previous Year Paper | CAT DILR | Set 3

CAT DI LR section has become increasingly tough beginning from 2015. DILR used to have distinct Data Interpretation sets and Logical reasoning puzzles. It used to be about computation and ability to read charts, graphs and tables for the Data Interpretation and Logical reasoning used to have Family tree, grid puzzles, arrangement, tournaments, cubes as some standard forms of puzzles.Since 2015 this pattern has been broken. With passing years, even the distinction between DI and LR has come down significantly. All you get in that one hour, are 8 high quality puzzles, with more than a few of them being significantly tough. Between CAT 2017 Question paper and CAT 2018 Question paper, you get to solve 32 actual CAT puzzles. This page intends to provide you just that. So, head on and crack those puzzles!

## CAT DILR : CAT 2018 Question Paper Slot 1

### Set 3 : N x N Square Matrix

You are given an n×n square matrix to be ﬁlled with numerals so that no two adjacent cells have the same numeral. Two cells are called adjacent if they touch each other horizontally, vertically or diagonally. So a cell in one of the four corners has three cells adjacent to it, and a cell in the ﬁrst or last row or column which is not in the corner has five cells adjacent to it. Any other cell has eight cells adjacent to it.

Question 2 : What is the minimum number of different numerals needed to ﬁll a 5×5 square matrix? [TITA]

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##### Method of solving this CAT Question on CAT DILR

Now, we have worked with a 3 x 3. We know that the 4 corner squares of the 3 x 3 can be the same number.
So, let us fill out a set of 3 x 3’s within this 5 x 5. We can build from there.

Now, let us fill out squares in between the 1’s row wise and then column wise.

Now, let us fill out squares in between the 1’s row wise and then column wise.
Now, this wonderful matrix fills itself. All the missing numbers should be the 4th numeral.
We know that to fill a mere 3 x 3 we needed at least 4 numerals.
If we have filled a 5 x 5 with 4 numerals, this fills me with enormous confidence.
Now, we can kill this set.

The question is "What is the minimum number of different numerals needed to ﬁll a 5×5 square matrix? [TITA]"

##### Hence, the answer is 4

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