CAT 2021 Question Paper | Quant Slot 1

CAT 2021 Quant was dominated by Arithmetic followed by Algebra. In Arithmetic, the questions were dominated by topics like Speed-time-distance, Mixture and Alligations. This year, there was a surprise. The questions from Geometry were relatively on the lower side as compared to the previous years. There were 8 TITA Qs this year. Overall this section was at a medium level of difficulty.

Question 5 : A basket of 2 apples, 4 oranges and 6 mangoes costs the same as a basket of 1 apple, 4 oranges and 8 mangoes, or a basket of 8 oranges and 7 mangoes. Then the number of mangoes in a basket of mangoes that has the same cost as the other baskets is

Video Explanation

Explanatory Answer

Let’s consider Apple, orange, mango to be x, y, z respectively.
Let's take the first two baskets and solve from there.
2x + 4y + 6z = x + 4y + 8z
 x = 2z.
Now, let’s take any other two different baskets and try to find the number of oranges in terms of the number of mangoes.
2x + 4y + 6z = 8y + 7z
2(2z) + 4y + 6z = 8y + 7z
y = \\frac{3}{4})z.
We need to find the value of one basket in terms of mangoes. So substitute x and y values in any one of the equations.
2x + 4y + 6z = 2(2z) + 4(\\frac{3}{4})z) + 6z = 13z.
13 mangoes worth of fruits is there in every basket.
Hence the answer is 13.

The answer is '13'

Choice B is the correct answer.

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