IIFT 2019 Question Paper | Quants

IIFT Previous Year Paper | IIFT Quants Questions | Question 21

The best way to boost your IIFT prep is to practice the actual IIFT Question Papers. 2IIM offers you exactly that, in a student friendly format to take value from this. In the 2019 IIFT, quants were a mixed bag of questions of varying difficulty, with some routine questions and the others were very demanding. Some beautiful questions that laid emphasis on Learning ideas from basics and being able to comprehend more than remembering gazillion formulae and shortcuts.

Question 21: If X = 8 - \sqrt{32} and Y = 2 + \sqrt{2} then (X+1/Y)2 is given by

  1. \\frac{16}{25}) x2
  2. \\frac{64}{81}) x2
  3. \\frac{25}{16}) x2
  4. \\frac{81}{64}) x2

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Explanatory Answer

From the given values of y we can find the value of 1/y:
\\frac{1}{y}) = \\frac{1}{2+\sqrt{2}}) \\frac{2-\sqrt{2}}{2-\sqrt{2}})
\\frac{1}{y}) = \\frac{2-\sqrt{2}}{2})
And
x = 8 - \\sqrt{32}
= 8 - \\frac{8}{\sqrt{2}})
= 8 (1 - \\frac{1}{\sqrt{2}}))
Then (x + 1/y) = 9 (1 - \\frac{1}{\sqrt{2}})
x+\\frac{1}{y}) = \\frac{9}{8}) x
=\\frac{81}{64}) x2


The question is "If X = 8 - \\sqrt{32} and Y = 2 + \\sqrt{2} then (X+1/Y)2 is given by

Hence, the answer is, "\\frac{81}{64}) x2"

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