CAT 2022 Quant was dominated by Arithmetic followed by Algebra. In Arithmetic, the questions were dominated by topics like Speed-time-distance, Mixture and Alligations. This year, there was a surprise. The questions from Geometry were relatively on the lower side as compared to the previous years. There were 8 TITA Qs this year. Overall this section was at a medium level of difficulty.
Question 1 : Let ABCD be a parallelogram such that the coordinates of its three vertices A, B, C are (1, 1), (3, 4) and (-2, 8), respectively. Then, the coordinates of the vertex D are
Let us locate the three given points on a 2D graph.
The fourth corner D of the parallelogram should be somewhere below and to the left of C.
Of the four options only (-4, 5) and (-3, 4) are below and to the left of C.
So, D can either be (-4, 5) or (-3, 4)
Since ABCD is a parallelogram, opposite sides should be parallel, or in other words, opposite sides should have the same slope.
The slope of AB = \(\frac{\Delta y}{\Delta x}=\frac{4-1}{3-1}=\frac{3}{2}\)
Slope of AB = Slope of DC = \(\frac{3}{2}\)
Only when the coordinates of point D are (-4, 5) will the slope of DC be \(\frac{3}{2}\).
Hence the coordinates of the fourth vertex of the parallelogram are (-4, 5)
Alternate Approach:
Observe that point C is 5 units to the left and 4 units above the point B.
Hence, point D should also be 5 units to the left and 4 units above point A.
Therefore the coordinates of point D are (1 - 5, 1 + 4) = (-4, 5).
The question is " Let ABCD be a parallelogram such that the coordinates of its three vertices A, B, C are (1, 1), (3, 4) and (-2, 8), respectively. Then, the coordinates of the vertex D are "
Choice A is the correct answer.
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