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Question 2 : A supplier receives orders from 5 different buyers. Each buyer places their order only on a Monday. The first buyer places the order after every 2 weeks, the second buyer, after every 6 weeks, the third buyer, after every 8 weeks, the fourth buyer, every 4 weeks, and the fifth buyer, after every 3 weeks. It is known that on January 1st, which was a Monday, each of these five buyers placed an order with the supplier.
On how many occasions, in the same year, will these buyers place their orders together excluding the order placed on January 1st?
First buyer - for every 2 weeks
Second buyer - for every 6 weeks
Third buyer - for every 8 weeks
Fourth buyer - for every 4 weeks
Fifth buyer - for every 3 weeks
It is given that they all have ordered on the day of Jan 01st.
We will get the next day when they all have ordered again by LCM of 2, 6, 8, 4, 3
L.C.M of 2, 6, 8, 4, 3 = 24
They all ordered on the 1st week, 25th week, and 49th week of the year.
Because we only need the number of times the transactions happened excluding the 1st week, the correct answer is 2.
Choice D is the correct answer.
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