CAT DI LR section has become increasingly tough beginning from 2015. DILR used to have distinct Data Interpretation sets and Logical reasoning puzzles. It used to be about computation and ability to read charts, graphs and tables for the Data Interpretation and Logical reasoning used to have Family tree, grid puzzles, arrangement, tournaments, cubes as some standard forms of puzzles.Since 2015 this pattern has been broken. With passing years, even the distinction between DI and LR has come down significantly. All you get in that one hour, are 8 high quality puzzles, with more than a few of them being significantly tough. Between CAT 2017 Question paper and CAT 2018 Question paper, you get to solve 32 actual CAT puzzles. This page intends to provide you just that. So, head on and crack those puzzles!

An agency entrusted to accredit colleges looks at four parameters: faculty quality (F), reputation (R), placement quality (P), and infrastructure (I). The four parameters are used to arrive at an overall score, which the agency uses to give an accreditation to the colleges. In each parameter, there are five possible letter grades given, each carrying certain points: A (50 points), B (40 points), C (30 points), D (20 points), and F (0 points). The overall score for a college is the weighted sum of the points scored in the four parameters. The weights of the parameters are 0.1, 0.2, 0.3 and 0.4 in some order, but the order is not disclosed.

Accreditation is awarded based on the following scheme:

Eight colleges apply for accreditation, and receive the following grades in the four parameters (F, R, P, and I):

It is further known that in terms of overall scores:

1. High Q is better than Best Ed.

2. Best Ed is better than Cosmopolitan.

3. Education Aid is better than A-one.

Question 3 : What is the highest overall score among the eight colleges? [TITA]

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Let us look at this one at a time. Statement 1 does not give us clear comparables, let us start with statement 2.

Ratings in F and P are identical, so we can infer that Weightage for R > Weightage for I.

R > I.

Now, let us move to statement 3.

Ratings in F and R are identical, so we can infer that Weightage for I > Weightage for P.

I > P.

Now, let us combine these two inferences – we get R > I > P.

Now, let us look at Statement 1.

Scores in P are identical. Best Ed has gotten better scores in F and R and a worse score in I.

Further Best Ed has gotten better score by one grade in F and R, but worse score by two grades in I.

So, Best Ed’s better score in two grades is more than offset by High Q’s better score in one parameter.

High Q is -1 in F and R, but +2 in I. We know that weightage given for R > I.

So, the -1 in R has a great impact, so the -1 in F should have much lower impact.

In other words, weightage for F should be small and that for I should be high.

Let us account for R > I > P first.

Of the 4 possibilities, we can easily eliminate the last one as F cannot be 0.4.

F cannot be 0.3 either, so the 3rd one can also be eliminated.

Even if F were 0.2, High Q would not be higher than Best End – the two scores would be equal.

So, the weightages have to be F = 0.1, R = 0.4, P = 0.2 and I = 0.3.

So, the weightages are as follows.

From the above table, we can see that the highest overall score among the eight colleges is 48.

The question is **"What is the highest overall score among the eight colleges? [TITA]" **

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