IPMAT Question Paper 2024 | IPM Indore Quantitative Ability

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Question 19 : Let ABC be an equilateral triangle, with each side of length k. If a circle is drawn with diameter AB, then the area of the portion of the triangle lying inside the circle is

1. \((3 \sqrt{3}+\pi)\left(\frac{k^2}{6}\right)\)
2. \((3 \sqrt{3}-\pi)\left(\frac{k^2}{24}\right)\)
3. \((3 \sqrt{3}+\pi)\left(\frac{k^2}{24}\right)\)
4. \((3 \sqrt{3}-\pi)\left(\frac{k^2}{6}\right)\)

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Video Explanation

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Explanatory Answer

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The question is "Let ABC be an equilateral triangle, with each side of length k. If a circle is drawn with diameter AB, then the area of the portion of the triangle lying inside the circle is"

Hence, the answer is '\((3 \sqrt{3}+\pi)\left(\frac{k^2}{24}\right)\)'

 

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