This gorgeous DILR question is based on satellites with a tinge of Set Theory! You can expect the Set Theory to loop in in many questions in this CAT Exam and it is advisable to have a good command of this concept. Why don't you try this one from CAT previous year paper and rock your CAT Online Preparation.
1600 satellites were sent up by a country for several purposes. The purposes are classified as broadcasting (B), communication (C), surveillance (S), and others (O). A satellite can serve multiple purposes; however a satellite serving either B, or C, or S does not serve O.
The following facts are known about the satellites:
1.The numbers of satellites serving B, C, and S (though may be not exclusively) are in the ratio 2:1:1.
2.The number of satellites serving all three of B, C, and S is 100.
3.The number of satellites exclusively serving C is the same as the number of satellites exclusively serving S. This number is 30% of the number of satellites exclusively serving B.
4.The number of satellites serving O is the same as the number of satellites serving both C and S but not B.
Question 1 : What best can be said about the number of satellites serving C?
1600 satellites were sent up by a country for several purposes. The purposes are classified as broadcasting (B), communication (C), surveillance (S), and others (O). A satellite can serve multiple purposes; however a satellite serving either B, or C, or S does not serve O.
Now, let us move to the equations.
We know that 2(m + 100 + 0.3y + k) = 2m + y + 100
Or, 2m + 200 + 0.6y + 2k = 2m + y + 100
100 + 2k = 0.4y
250 + 5k = y
We also know that 1.6y + 2m + 2k + 100 = 1600
1.6y + 2m + 2k = 1500
100 + 2k = 0.4y
250 + 5k = y
We also know that 1.6y + 2m + 2k + 100 = 1600
1.6y + 2m + 2k = 1500
1.6(250 + 5k) + 2m + 2k = 1500
400 + 8k + 2m + 2k = 1500
10k + 2m = 1100
5k + m = 550.
The two equations we have are
250 + 5k = y ---------- (1)
5k + m = 550. ---------- (2)
C has 100 + m + k + 0.3y satellites. This is equal to
100 + m + k + 0.3(250 + 5k) = 100 + m + k + 75 + 1.5k = 175 + 2.5k + m
= 175 + 550 – 2.5k = 725 – 2.5k
Think about the maximum and minimum this can take.
C has 725 – 2.5k
Think about the maximum and minimum this can take.
K can be 0, this will give us m of 550 and y = 250
This will give us a maximum value of 725.
We know that 5k + m = 550. So, maximum value of k is 110.
This gives us Cmin = 725 – (2.5 × 110) = 725 – 275 = 450.
C ranges from 450 to 725.
The question is "What best can be said about the number of satellites serving C?"
Choice D is the correct answer.
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