CAT 2018 Question Paper | CAT LR DI

CAT Previous Year Paper | CAT DILR | Set 2

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CAT DILR : CAT 2018 Question Paper Slot 1

Set 2 : Satellites

1600 satellites were sent up by a country for several purposes. The purposes are classified as broadcasting (B), communication (C), surveillance (S), and others (O). A satellite can serve multiple purposes; however a satellite serving either B, or C, or S does not serve O.
The following facts are known about the satellites:
1.The numbers of satellites serving B, C, and S (though may be not exclusively) are in the ratio 2:1:1.
2.The number of satellites serving all three of B, C, and S is 100.
3.The number of satellites exclusively serving C is the same as the number of satellites exclusively serving S. This number is 30% of the number of satellites exclusively serving B.
4.The number of satellites serving O is the same as the number of satellites serving both C and S but not B.

Question 2 : What is the minimum possible number of satellites serving B exclusively?

  1. 100
  2. 200
  3. 250
  4. 500

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Explanatory Answer

Method of solving this CAT Question on CAT DILR

1600 satellites were sent up by a country for several purposes. The purposes are classified as broadcasting (B), communication (C), surveillance (S), and others (O). A satellite can serve multiple purposes; however a satellite serving either B, or C, or S does not serve O.
CAT DI LR 2018 Slot 1
CAT DI LR 2018 Slot 1
CAT DI LR 2018 Slot 1
CAT DI LR 2018 Slot 1
CAT DI LR 2018 Slot 1
Now, let us move to the equations.
We know that 2(m + 100 + 0.3y + k) = 2m + y + 100
Or, 2m + 200 + 0.6y + 2k = 2m + y + 100
100 + 2k = 0.4y
250 + 5k = y
We also know that 1.6y + 2m + 2k + 100 = 1600
1.6y + 2m + 2k = 1500
100 + 2k = 0.4y
250 + 5k = y
We also know that 1.6y + 2m + 2k + 100 = 1600
1.6y + 2m + 2k = 1500
1.6(250 + 5k) + 2m + 2k = 1500
400 + 8k + 2m + 2k = 1500
10k + 2m = 1100
5k + m = 550.
The two equations we have are
250 + 5k = y ---------- (1)
5k + m = 550. ---------- (2)
Bexcl = y = 250 + 5k.
We already know k can be zero.
So, Bexcl-min = 250.

The question is "What is the minimum possible number of satellites serving B exclusively?"

Hence, the answer is 250

Choice C is the correct answer.

 

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