CAT 2018 Question Paper | CAT LR DI

CAT Previous Year Paper | CAT DILR | Set 2

To crush the DILR section of the CAT, start practicing various conundrums. Puzzles like sudoku and scrabble and help you hone your thinking skills and can help you remain sharp. Also, if you believe that you are confident enough to proceed, grab a few CAT previous year paper and begin solving. Now, solve this very problem from 2018 CAT question paper during your CAT online Coaching.

CAT DILR : CAT 2018 Question Paper Slot 1

Set 2 : Satellites

1600 satellites were sent up by a country for several purposes. The purposes are classified as broadcasting (B), communication (C), surveillance (S), and others (O). A satellite can serve multiple purposes; however a satellite serving either B, or C, or S does not serve O.
The following facts are known about the satellites:
1.The numbers of satellites serving B, C, and S (though may be not exclusively) are in the ratio 2:1:1.
2.The number of satellites serving all three of B, C, and S is 100.
3.The number of satellites exclusively serving C is the same as the number of satellites exclusively serving S. This number is 30% of the number of satellites exclusively serving B.
4.The number of satellites serving O is the same as the number of satellites serving both C and S but not B.

Question 2 : What is the minimum possible number of satellites serving B exclusively?

  1. 100
  2. 200
  3. 250
  4. 500

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Explanatory Answer

Method of solving this CAT Question on CAT DILR

1600 satellites were sent up by a country for several purposes. The purposes are classified as broadcasting (B), communication (C), surveillance (S), and others (O). A satellite can serve multiple purposes; however a satellite serving either B, or C, or S does not serve O.
CAT DI LR 2018 Slot 1
CAT DI LR 2018 Slot 1
CAT DI LR 2018 Slot 1
CAT DI LR 2018 Slot 1
CAT DI LR 2018 Slot 1
Now, let us move to the equations.
We know that 2(m + 100 + 0.3y + k) = 2m + y + 100
Or, 2m + 200 + 0.6y + 2k = 2m + y + 100
100 + 2k = 0.4y
250 + 5k = y
We also know that 1.6y + 2m + 2k + 100 = 1600
1.6y + 2m + 2k = 1500
100 + 2k = 0.4y
250 + 5k = y
We also know that 1.6y + 2m + 2k + 100 = 1600
1.6y + 2m + 2k = 1500
1.6(250 + 5k) + 2m + 2k = 1500
400 + 8k + 2m + 2k = 1500
10k + 2m = 1100
5k + m = 550.
The two equations we have are
250 + 5k = y ---------- (1)
5k + m = 550. ---------- (2)
Bexcl = y = 250 + 5k.
We already know k can be zero.
So, Bexcl-min = 250.

The question is "What is the minimum possible number of satellites serving B exclusively?"

Hence, the answer is 250

Choice C is the correct answer.

 

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