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CAT Previous Year Paper | CAT Quants Questions | Question 24

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Question 24 : Aron bought some pencils and sharpeners. Spending the same amount of money as Aron, Aditya bought twice as many pencils and 10 less sharpeners. If the cost of one sharpener is 2 more than the cost of a pencil, then the minimum possible number of pencils bought by Aron and Aditya together is

  1. 33
  2. 27
  3. 30
  4. 36

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Explanatory Answer

  Pencils and it's price = x Sharpeners and it’s price = x+2
Aron p s
Aditya 2p s-10

(Aron) Px + sx + 2s = (Aditya) 2px + sx – 20 – 10x + 2s
Px = 10x + 20
x(p-10) = 20
Together they bought 3p pencils
Minimum value of p has to be 11
So, minimum pencils they bought together is 33


The answer is, "33"

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