# CAT 2020 Question Paper | Quants Slot 3

###### CAT Previous Year Paper | CAT Quants Questions | Question 22

This question is from Speed time distance. Questions from Speed time distance have appeared in every edition of the CAT Exam. This is a very interesting topic as it can be relatable in real-life scenarios too. If you're in a hurry, then solve this question. This question might help you to calculate how late you're going to be. To explore 1000+ intriguing questions, check out 2IIM CAT Question Bank, and give your CAT Preparation the right direction.

Question 22 : Vimla starts for office every day at 9 am and reaches exactly on time if she drives at her usual speed of 40 km/hr. She is late by 6 minutes if she drives at 35 km/hr. One day, she covers two-thirds of her distance to office in one-thirds of her usual time to reach office, and then stops for 8 minutes. The speed, in km/hr, at which she should drive the remaining distance to reach office exactly on time is

1. 27
2. 28
3. 29
4. 26

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Vimala's speed has decreased from 40kmph to 35 kmph. That means her current speed is $$frac{35}{40}$ of the original Speed. That means, her current speed is $\frac{7}{8}$ th of the original speed. Therefore, the time taken will be $\frac{8}{7}$ th of the original time taken. Since she is 6 minutes late when travelling at 35kmph, $\frac{1}{7}$th of the original time taken is 6 minutes. Therefore the total time taken originally is 7 × 6 = 42 minutes. $\frac{1}{3}$ rd of the original time taken = $\frac{42}{3}$ = 14 minutes. $\frac{1}{3}$ rd of the total distance is generally covered in 14 minutes. Currently the same distance is to be covered in$42 - 14 - 8 = 20) minutes.