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Question 12 : Suppose that log2[log3 (log4a)] = log3 [log4 (log2b)] = log4 [log2 (log3c)] = 0 then the value of a + b + c is
log2[log3 (log4a)] = log3 [log4 (log2b)] = log4 [log2 (log3c)] = 0
Let us take log2[log3 (log4a)] = 0
log3 (log4a) = 20 = 1 [ since lognM = k ⇒ M = nk]
log3 (log4a) = 1
log4a = 31 = 3
log4a = 3
a = 43 = 64
Now let us take log3 [log4 (log2b)] = 0
log4 (log2b)] = 1
log2b = 4
b = 24 = 16
Now let us take last part log4 [log2 (log3c)] = 0
log2 (log3c) = 1
log3c = 2
c = 32 = 9
Therefore the value of a + b + c = 64 + 16 + 9 = 89
Choice C is the correct answer.
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