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Question 20 : Please calculate in how many ways can a set of five players be formed out of a total of ten players such that two particular players should be involved in each set?
Since 2 players are already fixed, that is they are always in the team...,
The question now boils down to finding the number of ways in which the remaining 3 players can be chosen from the rest of 8 players...
This can be done in 8C3 ways = 56 ways.
The question is " Please calculate in how many ways can a set of five players be formed out of a total of ten players such that two particular players should be involved in each set? "
Choice C is the correct answer.
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