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Question 2 : If f(5 + x) = f(5 - x) for every real x and f(x) = 0 has four distinct real roots, then the sum of the roots is
Given f (5 + x) = f (5 – x)
When x = 1, f(6) = f(4)
When x = 2, f(7) = f(3)
Imagine a graph and while joining (6,4) and (7,3) it looks symmetrical about 5
Given 4 distinct real roots. Assume 12 as one of the roots.
f(12) = 0 --> Then f(5 + 7) = 0 which is same as f(5 – 7) = f(-2) = 0
So the roots are in the form (5 + k) and (5 – k) {This is one pair}
Sum of the roots = 5 + k + 5 – k = 10
We have 4 roots, So two pairs =10 + 10 = 20
The question is "If f(5 + x) = f(5 - x) for every real x and f(x) = 0 has four distinct real roots, then the sum of the roots is"
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