This question is from Mixture and Alligation. This question talks about a solution that consists of dye and water in a specified proportion. We need to find the quantity of dye that is needed to be added to achieve the initial proportion of dye and water after some alteration. **The importance of Arithmetic questions** has increased significantly in the **CAT exam**. The Arithmetic section plays a pivotal role in your **CAT Preparation**. Make sure you master this topic by practicing a lot of questions from the **2IIM CAT Question Bank**.

Question 26 : A solution, of volume 40 litres, has dye and water in the proportion 2 : 3. Water is added to the solution to change this proportion to 2 : 5. If one-fourths of this diluted solution is taken out, how many litres of dye must be added to the remaining solution to bring the proportion back to 2 : 3?

Limited Seats Available - Register Now!

40 litres is split in ratio 2:3

So dye = 16 l and water = 24 l

Now proportion is 2:5

Already in the ratios 2:3

2 : 5

Now, 16 l of dye : 40 l of water

16 l of water is added

\\frac{1}{4})th is removed from the proportion

12 l of dye : 30 l of water

Now how many dye has to be added to make 2 : 3

2 : 3

12 l of dye : 30 l of water

Multiplication factor is 10 (3 × 10 = 30)

2 × 10 = 20 l of dye in total,

So 8 l of dye has to be added

Copyrights © All Rights Reserved by 2IIM.com - A Fermat Education Initiative.

Privacy Policy | Terms & Conditions

CAT^{®} (Common Admission Test) is a registered trademark of the Indian Institutes of Management. This website is not endorsed or approved by IIMs.

2IIM Online CAT Coaching

A Fermat Education Initiative,

58/16, Indira Gandhi Street,

Kaveri Rangan Nagar, Saligramam, Chennai 600 093

**Mobile:** (91) 99626 48484 / 94459 38484

**WhatsApp:** WhatsApp Now

**Email: **info@2iim.com