A very straightforward arithmetic question similar to the ones we have seen in **CAT previous year paper**. It involves probably 2 concepts from **Percentages** & Ratio proportion. Good diligence will ensure accuracy in these questions. Going through a lot of Mechanical preparation will help you quickly solve this question & put it in your bag.

Question 11 : A person invested a total amount of Rs 15 lakh. A part of it was invested in a fixed deposit earning 6% annual interest, and the remaining amount was invested in two other deposits in the ratio 2 : 1, earning annual interest at the rates of 4% and 3%, respectively. If the total annual interest income is Rs 76000 then the amount (in Rs lakh) invested in the fixed deposit was [TITA]

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Let Rs x be invested in FD.

So, Remaining amount = Rs. 15 Lakhs - x, which is invested in the ratio 2 : 1

So, each investment would have (15-x) and (15-x) investments respectively

So, Total annual interest income = 6% of x + 4% of (15-x) + 3% of (15-x) = 76000

Rewriting Rs. 76000 as Rs. 0.76 Lakhs,

6% of x + 4% of (15-x) + 3% of (15-x) = 0.76

Multiply both sides by 100,

6x + (15-x) + 2(15-x) = 76

6x + (15-x) = 76

165 + 18x -11x = 228

7x = 63

x = 9 (or) Rs. 9 Lakhs

The question is **"A person invested a total amount of Rs 15 lakh. A part of it was invested in a fixed deposit earning 6% annual interest, and the remaining amount was invested in two other deposits in the ratio 2 : 1, earning annual interest at the rates of 4% and 3%, respectively. If the total annual interest income is Rs 76000 then the amount (in Rs lakh) invested in the fixed deposit was [TITA] " **

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