Speed Time Distance is generally well understood by the CAT aspirants however they do find themselves caught up in solving trickier questions that we can expect in the CAT exam. To have a smooth ride while attempting the CAT Question Paper it is important to level up your CAT online preparation. One good way to go about it is to practice questions from CAT previous year paper. They help you come face to face with the questions you can expect in the upcoming exam and give you a sense of how to find your way about the trickier questions. Gear up your preparation levels by starting off with this question from Speed Time Distance that appeared in CAT 2019 Question Paper - Slot 2.
Question 12 : A cyclist leaves A at 10 am and reaches B at 11 am. Starting from 10:01 am, every minute a motorcycle leaves A and moves towards B. Forty-five such motorcycles reach B by 11 am. All motorcycles have the same speed. If the cyclist had doubled his speed, how many motorcycles would have reached B by the time the cyclist reached B?
It is given that the cyclist starts at 10:00 am from A and reaches B at 11:00 am
Now, Motorcyclists start every minute from 10:01 am, and 45 such motorcyclists reach B before 11:00 am
If they leave one by one every minute, the 45th motorcyclist would have left by 10:45 am to reach B at 11:00 am.
Thus, time taken by one motorcyclist to reach B from A = 15 minutes.
Now, the cyclist doubles his speed. This means, he reaches B at 10:30 am
So, the last motorcyclist should have left A by 10:15 am
Thus, 15 motorcyclists would have reached B by the time the cyclist reaches B
The question is "A cyclist leaves A at 10 am and reaches B at 11 am. Starting from 10:01 am, every minute a motorcycle leaves A and moves towards B. Forty-five such motorcycles reach B by 11 am. All motorcycles have the same speed. If the cyclist had doubled his speed, how many motorcycles would have reached B by the time the cyclist reached B? "
Choice C is the correct answer.
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