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Question 26 : In a six-digit number, the sixth, that is, the rightmost, digit is the sum of the first three digits, the fifth digit is the sum of first two digits, the third digit is equal to the first digit, the second digit is twice the first digit and the fourth digit is the sum of fifth and sixth digits. Then, the largest possible value of the fourth digit is [TITA]


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Explanatory Answer




Let the first digit be = a
Second digit = Twice of first digit = 2a
Third digit = First digit = a
Fifth digit = Sum of first two digits = a + 2a = 3a
Sixth digit = Sum of first three digits = a + 2a + a = 4a
Fourth digit = Sum of fifth and sixth digit = 3a + 4a = 7a

Largest possible value of fourth digit = 7 (any more than that would be > 10 and not satisfy the condition)


The question is "In a six-digit number, the sixth, that is, the rightmost, digit is the sum of the first three digits, the fifth digit is the sum of first two digits, the third digit is equal to the first digit, the second digit is twice the first digit and the fourth digit is the sum of fifth and sixth digits. Then, the largest possible value of the fourth digit is [TITA]"

Hence, the answer is 7

 

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