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Question 20 : Let ABC be a right-angled triangle with hypotenuse BC of length 20 cm. If AP is perpendicular on BC, then the maximum possible length of AP, in cm, is
Now, the length of AP would be maximum, when AB = AC (ABC is an Isosceles Right Triangle)
So, AB = AC = 10cms
Applying Pythagoras theorem to APB, we get
AB2 = AP2 + PB2
(102 = 102 + x2
x2 = 100
x = 10 cms
The question is "Let ABC be a right-angled triangle with hypotenuse BC of length 20 cm. If AP is perpendicular on BC, then the maximum possible length of AP, in cm, is"
Choice A is the correct answer.
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