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Question 20 : Let ABC be a right-angled triangle with hypotenuse BC of length 20 cm. If AP is perpendicular on BC, then the maximum possible length of AP, in cm, is

  1. 10
  2. 8\\sqrt{2})
  3. 6\\sqrt{2})
  4. 5

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Explanatory Answer



Now, the length of AP would be maximum, when AB = AC (ABC is an Isosceles Right Triangle)
So, AB = AC = 10cms
Applying Pythagoras theorem to APB, we get
AB2 = AP2 + PB2
(102 = 102 + x2
x2 = 100
x = 10 cms


The question is "Let ABC be a right-angled triangle with hypotenuse BC of length 20 cm. If AP is perpendicular on BC, then the maximum possible length of AP, in cm, is"

Hence, the answer is 10

Choice A is the correct answer.

 

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