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Question 8 : What is the largest positive integer such that \\frac{n^2+7n+12}{n^2-n-12}) is also positive integer?

  1. 6
  2. 8
  3. 16
  4. 12

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Explanatory Answer

can be rewritten as
= 1 +
1 + = 1 +
n cannot be -3
has to be an integer
And this value has to be equal to 1, for n to be high
So,= 1
8 = n - 4
n = 12

The question is "What is the largest positive integer such that \\frac{n^2+7n+12}{n^2-n-12}) is also positive integer? "

Hence, the answer is 12

Choice D is the correct answer.


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