CAT 2019 Question Paper | Quants Slot 2

CAT Previous Year Paper | CAT Quants Questions | Question 30

Mixtures and Alligations is one very interesting topic tested in the CAT exam. It falls under the Arithmetic part of the Quantitative Ability section and hence is as crucial as the other topics under this part. Questions on mixtures are trickier to solve as they involve the understanding of concepts from the topics of Percentages and Ratio and proportion as well. To be able to solve all these questions efficiently and without making errors, it is important that you practice CAT previous year paper questions and strengthen your CAT preparation online. Start with this question right now!

Question 30 : The strength of a salt solution is p% if 100 ml of the solution contains p grams of salt. Each of three vessels A, B, C contains 500 ml of salt solution of strengths 10%, 22%, and 32%, respectively. Now, 100 ml of the solution in vessel A is transferred to vessel B. Then, 100 ml of the solution in vessel B is transferred to vessel C. Finally, 100 ml of the solution in vessel C is transferred to vessel A. The strength, in percentage, of the resulting solution in vessel A is

  1. 15
  2. 12
  3. 13
  4. 14

🎉Grab a Vijayadashami & Dussehra Discount of up to ₹ 12,000 on 2024 & 2025 CAT courses! Offer valid until 12th October.


Register Now

🎉 2IIM CAT Revision Course 2024: 100+ Hours of Intensive Prep and everything is covered—Join Now!!! 🎉


Register Now


Video Explanation


Best CAT Coaching in Chennai


CAT Coaching in Chennai - CAT 2022
Limited Seats Available - Register Now!


Explanatory Answer

Vessels A, B and C contains salt solution of strengths 10%, 22% and 32% respectively
It is also given that the amount of salt solution = 500 ml
So, Vessels A, B and C contains salt of 50 grams, 110 grams and 160 grams respectively

100 ml of Solution is transferred from A to B:
A would have 400 ml, B would have 600 ml of solution
Amount salt from A which is transferred to B = = 10 grams
So, Total salt in B = 110 + 10 = 120 grams (After first transfer)
Total salt in A = 40 grams (After first transfer)

Now, 100 ml from Vessel B is transferred to Vessel C
So similarly, of salt would transfer from B to C
Total Salt in B = 120 - 20 = 100 grams (After second transfer)
Total Salt in C = 160 + 20 = 180 grams (After second transfer)

Now, 100 ml from Vessel C is transferred to Vessel A
So similarly, of salt would transfer from C to A
Total Salt in C = 160 - 30 = 130 grams (After third transfer)
Total Salt in A = 40 + 30 = 70 grams (After third transfer)

So, Vessel A contains 70 grams Salt in 500 ml solution
Strength of Salt Solution in Vessel A = 14%


Choice D is the correct answer.

 

CAT Questions | CAT Quantitative Aptitude

CAT Questions | Verbal Ability for CAT


Where is 2IIM located?

2IIM Online CAT Coaching
A Fermat Education Initiative,
58/16, Indira Gandhi Street,
Kaveri Rangan Nagar, Saligramam, Chennai 600 093

How to reach 2IIM?

Mobile: (91) 99626 48484 / 94459 38484
WhatsApp: WhatsApp Now
Email: info@2iim.com