# IPMAT Question Paper 2020 | IPM Indore Quants

###### IPMAT Sample Paper | IPMAT Question Paper | Question 13

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Question 13 : The equation of the straight line passing through the point M (-5,1), such that the portion of it between the axes is divided by the point M in to two equal halves, is

1. 10y - 8x = 80
2. 8y + 10x = 80
3. 10y + 8x = 80
4. 8y + 10x + 80 = 0

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The point P divides AB into 2 halves.
AP = PB
A is on the x axis, Hence Point A (h,0)
B is on the Y axis, Hence Point B (0,k)

We need to use midpoint formula.
[$$frac{$h + 0$}{2}) , $$frac{$k + 0$}{2})] = (-5 , 4)
$$frac{h}{2}$ = - 5 h = -10 $\frac{k}{2} = 4 k = 8 Hence the Y intercept is 8 and X intercept is - 10. \\frac{x}{-10}$ + $\frac{y}{8}$ = 1 -8x + 10y = 80 The equation is -8x + 10y = 80 The question is " The equation of the straight line passing through the point M$-5,1), such that the portion of it between the axes is divided by the point M in to two equal halves, is "

##### Hence, the answer is 10y - 8x = 80

Choice A is the correct answer.

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