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Question 14 : The value of cos2\\frac{π}{8}) + cos2\\frac{3π}{8}) + cos2\\frac{5π}{8}) + cos2\\frac{7π}{8}) is
Now adding cos2\\frac{π}{8}) and cos2\\frac{7π}{8})
Then cos2\\frac{3π}{8}) and cos2\\frac{5π}{8})
cos2\\frac{π}{8}) is same as cos2\\frac{7π}{8})
cos2\\frac{3π}{8}) is same as cos2\\frac{5π}{8})
Question can be rephrased as 2cos2\\frac{π}{8}) + 2cos2\\frac{3π}{8})
\\frac{π}{8}) + \\frac{3π}{8}) = \\frac{π}{2})
cos(90 - θ) = sin θ
So, cos2\\frac{3π}{8}) = sin2\\frac{π}{8})
2cos2\\frac{π}{8}) + 2sin2\\frac{π}{8})
2[cos2 θ + sin2 θ]
2[1] = 2
The question is " The value of cos2\\frac{π}{8}) + cos2\\frac{3π}{8}) + cos2\\frac{5π}{8}) + cos2\\frac{7π}{8}) is "
Choice C is the correct answer.
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