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Question 23 : A 2 × 2 matrix is filled with four distinct integers randomly chosen from the set {1,2,3,4,5,6} Then the probability that the matrix generated in such a way is singular is
A matrix is singular if and only if the determinant of the matrix is 0.
In a 2 × 2 matrix,
\\left|\begin{array}{cc}a & c \\d & b\end{array}\right| \\) = ab - cd = 0
Or ab = cd
If one of a,b,c or d is 5, then ab ≠ cd, because in the set {1,2,3,4,5,6} there is only one multiple of 5.
So, we just have the set {1,2,3,4,6} to deal with and out of these we'll have select 4 integers.
We can't pick either 3 or 6. We'll have to pick them both.
That is 3 and 6 have to stay on either side of the equation ab = cd
So, the equation now becomes, 3b = 6d
Clearly, b > d
{b, d} ⊂ {1, 2, 4}
If b = 4, d = 2
If b = 2, d = 1
So, only two such combinations exist.
{a, b, c, d} = {1, 2, 3, 6} or {a, b, c, d} = {4, 2, 3, 6}
We can select four numbers from the six in 6C4 = 15 ways
After selecting the 4 integers, we can arrange them in order in 4! ways.
So, the total number of matrices that can be constructed = 15 × 4!
Once we select {a, b, c, d} = {1, 2, 3, 6} or {a, b, c, d} = {4, 2, 3, 6},
To construct a singular matrix, for example, 2 & 3 should be on the same diagonal. Similarly, 4 & 3 too in case of {a, b, c, d} = {4, 2, 3, 6}.
Only one-third of the arrangments yeild a singular matrix and the others dont.
But the probabilty of getting a singular matrix = \\frac{2 × 4! ÷ 3}{15 × 4!}) = \\frac{2}{45})
The question is " A 2 × 2 matrix is filled with four distinct integers randomly chosen from the set {1,2,3,4,5,6} Then the probability that the matrix generated in such a way is singular is "
Choicve A is the correct answer.
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