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Question 35: Two points on a ground are 1 m apart. If a cow moves in the field in such a way that it's distance from the two points is always in ratio 3: 2 then
Let us say that the cow moves between the points O and A which are 1m apart.
For convenience, Let us fix O at (0,0) and A at (1,0).
Let us assume that B is at some point (x,y) where the cow is grazing. Let P be the perpendicular dropped from B on OA.
So OP = x and PA = 1-x
OB2= OP2+ BP2= x2+ y2
OB =\\sqrt{x^{2} + y^{2}}\\)
BA2= AP2+ BP2
BA2= (1-x)2+ y2
BA = \\sqrt{(1-x)^{2} + y^{2}}\\)
Also, \\frac{OB}{BA}\\) = \\frac{3}{2}\\)
\\frac{\sqrt{x^{2} + y^{2}}}{\sqrt{(1-x)^{2} + y^{2}}}\\) = \\frac{3}{2}\\)
\\frac{x^{2} + y^{2}}{(1-x)^{2} + y^{2}}\\) = \\frac{9}{4}\\)
4(x2+ y2) = 9((1−x)2+ y2) = 9 (1 + x2– 2x + y2)
4 x2+ 4 y2= 9 + 9 x2– 18x + 9y2
5x2 + 5y2 – 18x +9 = 0, This is an equation of locus of a Circle.
Hence, the cow moves in a Circular path.
The question is"Two points on a ground are 1 m apart. If a cow moves in the field in such a way that it's distance from the two points is always in ratio 3: 2 then"
Choice B is the correct answer
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