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Question 37 : If \\sin \theta + \cos \theta = m,\\) then \\sin ^{6} \theta + \cos ^{6} \theta\\) equals

- \\frac{3(m^{2}+1)}{4}\\)
- \\frac{3(m^{2}-1)}{4}\\)
- \1-\frac{3(m^{2}-1)}{4}\\)
- \1-\frac{3(m^{2}-1)^{2}}{4}\\)

\1-\frac{3(m^{2}-1)^{2}}{4}\\)

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The question is **"If \\sin \theta + \cos \theta = m,\\) then \\sin ^{6} \theta + \cos ^{6} \theta\\) equals" **

Choice D is the correct answer

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