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CAT 2018 Question Paper | Quants Slot 2
CAT Previous Year Paper | CAT Sequence and Series Questions | Question 16
CAT Questions You can expect at least one question from Sequences and Series topic in the CAT Exam. This CAT 2018 Question Paper is no exception. Make sure you are doubly thorough with your concepts while taking up the CAT Online Preparation. CAT Quants require some specific strateges, and to learn about the preparation techniques, click: How to prepare for Quant.
Question 16 : The value of the sum 7 x 11 + 11 x 15 + 15 x 19 + ..... + 95 x 99 is
- 80707
- 80751
- 80730
- 80773
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Explanatory Answer
Method of solving this CAT Question from Sequence and Series
Here we have to find the value of the sum 7 × 11 + 11 × 15 + 15 × 19 + ..... + 95 × 99
Tn = (4n + 3) (4n + 7)
Since increment of 4 takes place in every value , 4n is the term to be used
T1 = (4 + 3) (4 + 7) = 7 × 11
T2 = 11 × 15
T3 = 15 × 19 and so on
Expanding Tn = (4n + 3) (4n + 7)
We will get 16n2 + 12n + 28n +21
16n2 + 40n +21
Σ16n2 + 40 Σn + 21 Σ1
\\frac{16n(n+1)(2n+1)}{6}) + \\frac{40n(n+1)}{2}) + 21 × n
Simplifying this we can take n out
n[\\frac{8n(n+1)(2n+1)}{3}) + 20(n+1) + 21]
From the options we can take 80707 and check whether it is divisible by 23
\\frac{80707}{23}) = 3509
⟹ option a) 80707 is a multiple of 23
⟹ option b) 80751 is 80707 + 44 so this doesn’t work
⟹ option c) 80730 is 80707 + 23 so this is also a multiple of 23
⟹ option d) 80773 is 80707 + 66 so this also doesn’t work
So let us check out with option a and c so we have to substitute and simplify and find
n[\\frac{8n(n+1)(2n+1)}{3}) + 20(n+1) + 21]
\\frac{n}{3})[8(n+1)(2n+1) + 60(n+1) + 63]
From the answer choices we have only two possibilities left out i.e. 23 ⨯ 3509 or 23 ⨯ 3510
⟹ \\frac{23}{3})[8(23 + 1)(2(23) + 1) + 60(23 + 1) + 63]
⟹ \\frac{23}{3})[8(24)(47) + 60 (24) + 63]
⟹ \\frac{23}{3})[8(24)(47) + 60 (24) + 63]
⟹ 23[8(8)(47) + 60 (8) + 21]
⟹ 80707
Hence the value of the sum 7 × 11 + 11 × 15 + 15 × 19 + ..... + 95 × 99 is 80707
The question is "The value of the sum 7 x 11 + 11 x 15 + 15 x 19 + ..... + 95 x 99 is"
Hence, the answer is 80707
Choice A is the correct answer.
