CAT 2018 Question Paper | Quants Slot 2

CAT Previous Year Paper | CAT Ratio and Proportion Questions | Question 3

The best questions to practice for CAT Exam are the actual CAT Question Papers. 2IIM offers you exactly that, in a student friendly format to take value from this. If you would like to take the same inside a testing engine (for Free) head out here: CAT Official Question Mocks. In CAT 2018 we saw some beautiful questions that laid emphasis on Learning ideas from basics and being able to comprehend more than remembering gazillion formulae and shortcuts. Original CAT Question paper is the best place to start off your CAT prep practice. This page provides exactly that. To check out about 1000 CAT Level questions with detailed video solutions for free, go here: CAT Question Bank

Question 3 : There are two drums, each containing a mixture of paints A and B. In drum 1, A and B are in the ratio 18 : 7. The mixtures from drums 1 and 2 are mixed in the ratio 3 : 4 and in this final mixture, A and B are in the ratio 13 : 7. In drum 2, then A and B were in the ratio

1. 251 : 163
2. 239 : 161
3. 220 : 149
4. 229 : 141

Best CAT Coaching in Chennai

Explanatory Answer

Method of solving this CAT Question from Ratio and Proportion

Given that two drums each containing a mixture of paints A and B. In drum 1, A and B are in the ratio 18 : 7. Drums 1 and 2 are mixed in the ratio 3 : 4 and in the final mixture A and B are in the ratio 13 : 7. For these kinds of questions do not consider separately as A and B. Deal with either A or B as a share of overall
Here A is $$frac{18}{25}$ of overall In D2, let us assume the proportion of A with respect to the overall mixture is x. 3 parts of D1 is mixed with parts of D2 to give proportion of A of which is $\frac{13}{20}$th of the overall mixture. From here on, it is weighted averages. So, $\frac{\frac{18}{5} × 3 + 𝑥 × 4}{7}$ = $\frac{13}{20}$ $\frac{54}{25}$ + 4𝑥 = $\frac{91}{20}$ 4𝑥 = $\frac{91}{20}$ - $\frac{54}{25}$ 4𝑥 = $\frac{455 - 216}{100}$ = $\frac{239}{100}$ 𝑥 = $\frac{239}{400}$ In drum 2, A is $\frac{239}{400}$ so B should be the remaining. Therefore, A : B = 239 : 161 The question is "There are two drums, each containing a mixture of paints A and B. In drum 1, A and B are in the ratio 18 : 7. The mixtures from drums 1 and 2 are mixed in the ratio 3 : 4 and in this final mixture, A and B are in the ratio 13 : 7. In drum 2, then A and B were in the ratio " Hence, the answer is 239 : 161 Choice B is the correct answer. 2IIM's Online CAT CoachingGet CAT Last Mile Prep Course for 799 /- Signup Now! Already have an Account? CAT Coaching in ChennaiCAT 2020Enroll at 44,000/- Next Weekend Batch Starts Sat, Nov 2nd, 2019 Best CAT Coaching in ChennaiRegister Online, get Rs 4000/- off Attend a Demo Class Where is 2IIM located? 2IIM Online CAT Coaching A Fermat Education Initiative, 58/16, Indira Gandhi Street, Kaveri Rangan Nagar, Saligramam, Chennai 600 093 How to reach 2IIM? Phone:$91) 44 4505 8484
Mobile: (91) 99626 48484
WhatsApp: WhatsApp Now
Email: prep@2iim.com