Mixtures is a very important topic in the Quantitative Aptitude section of the **CAT Exam**. And hence, requires your thorough practice to ace your **CAT online preparation**. Can't find a starting point? Start right here with this fabulous question on Mixtures from CAT previous year paper 2018.

Question 19 : A jar contains a mixture of 175 ml water and 700 ml alcohol. Gopal takes out 10% of the mixture and substitutes it by water of the same amount. The process is repeated once again. The percentage of water in the mixture is now

- 25.4
- 20.5
- 30.3
- 35.2

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Given that a jar contains a mixture of 175 ml water and 700 ml alcohol.

It is given that 10% of the mixture is removed and it is substituted by water of the same amount and the process is repeated once again

Now we have to find the percentage of water in the mixture.

Since the mixture is removed and substituted with water, we can deal with alcohol and the second step we can find how much amount of alcohol is retained and not about how much amount of alcohol is removed

As 10% of alcohol is removed, 90% of alcohol is retained

So alcohol remaining = 700 × 90% × 90%

⟹ 700 × 0.9 × 0.9 = 567

We totally have 875 ml overall mixture and of this 567 ml is alcohol.

Remaining 875 – 567 = 308 is the amount of water.

We have to find the percentage of water in the mixture i.e. \\frac{308}{875})

Approximately 308 is 30% of 1000 so by this we know that 308 is more than 30%

Hence 35.2% is the percentage of water in the given mixture.

The question is **"A jar contains a mixture of 175 ml water and 700 ml alcohol. Gopal takes out 10% of the mixture and substitutes it by water of the same amount. The process is repeated once again. The percentage of water in the mixture is now"**

Choice D is the correct answer.

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