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Question 14 : Consider three mixtures - the first having water and liquid A in the ratio 1 : 2, the second having water and liquid B in the ratio 1 : 3, and the third having water and liquid C in the ratio 1 : 4. These three mixtures of A, B, and C, respectively, are further mixed in the proportion 4 : 3 : 2. Then the resulting mixture has

1. The same amount of water and liquid B
2. The same amount of liquids B and C
3. More water than liquid B
4. More water than liquid A

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Video Explanation

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Explanatory Answer

Method of solving this CAT Question from Mixtures

There are three mixtures ,the first having water and liquid A in the ratio 1 : 2,
so we can consider only the liquid part which is \\frac{2}{3}).
The second having the water and liquid in the ratio 1 : 3 = \\frac{3}{4}).
The third having the liquid and water in the ratio 1 : 4 = \\frac{4}{5})

⟹ \\frac{160x}{60}) + \\frac{135x}{60}) + \\frac{96x}{60}) = \\frac{391x}{60})
⟹ \\frac{540x}{60}) - \\frac{391x}{60}) = \\frac{149x}{60}) = 2\\frac{29}{60})x
Where A = 2\\frac{2}{3})x and B = 2\\frac{1}{4})x
Hence by this we can infer that more water than liquid B is true

The question is "Consider three mixtures - the first having water and liquid A in the ratio 1 : 2, the second having water and liquid B in the ratio 1 : 3, and the third having water and liquid C in the ratio 1 : 4. These three mixtures of A, B, and C, respectively, are further mixed in the proportion 4 : 3 : 2. Then the resulting mixture has"

Hence, the answer is More water than liquid B

Choice C is the correct answer