One very important element of your ** CAT Preparation Online ** is practising the ** CAT previous year paper**. They not only help you glide smoothly through the concepts but also guide you on the slippery slope of questions you can expect in your actual CAT Question Paper. Try this question from progression taken from CAT Question Paper 2017 Slot 2 and start practicing the previous year questions right away!

Question 27 : Let a_{1}, a_{2}, a_{3}, a_{4}, a_{5} be a sequence of five consecutive odd numbers. Consider a new sequence of five consecutive even numbers ending with 2a_{3}. If the sum of the numbers in the new sequence is 450, then a_{5} is [TITA]

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Let a_{1}, a_{2}, a_{3}, a_{4}, a_{5} be n - 4 , n - 2 , n , n + 2 ,n + 4 respectively which is the sequence of consecutive odd numbers, where n = a_{3}.

Let the new sequence of five consecutive even numbers be m - 4, m - 2, m, m + 2, m + 4.

Where the last term m + 4 = 2a_{3} = 450

Average of any number of terms in AP is the middle term

5 terms in AP ⟹ 5 × (middle term) = 450

⟹ Middle term (m) = 90

⟹ m - 4, m - 2, m, m + 2, m + 4 is equal to 86, 88, 90, 92, and 94 respectively.

⟹ 2a_{3} = 94

⟹ a_{3} = \\frac{94}{2}) = 47

Hence a_{1}, a_{2}, a_{3}, a_{4}, a_{5} is equal to 43, 45, 47, 49, and 51 respectively.

Therefore a_{5} = 51

The question is **"Let a _{1}, a_{2}, a_{3}, a_{4}, a_{5} be a sequence of five consecutive odd numbers. Consider a new sequence of five consecutive even numbers ending with 2a_{3}. If the sum of the numbers in the new sequence is 450, then a_{5} is [TITA]" **

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