# CAT 2017 Question Paper | Quants Slot 2

###### CAT Previous Year Paper | CAT Progressions Questions | Question 27

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Question 27 : Let a1, a2, a3, a4, a5 be a sequence of five consecutive odd numbers. Consider a new sequence of five consecutive even numbers ending with 2a3. If the sum of the numbers in the new sequence is 450, then a5 is [TITA]

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##### Method of solving this CAT Question from Progressions

Let a1, a2, a3, a4, a5 be n - 4 , n - 2 , n , n + 2 ,n + 4 respectively which is the sequence of consecutive odd numbers, where n = a3.
Let the new sequence of five consecutive even numbers be m - 4, m - 2, m, m + 2, m + 4.
Where the last term m + 4 = 2a3 = 450
Average of any number of terms in AP is the middle term
5 terms in AP ⟹ 5 × (middle term) = 450
⟹ Middle term (m) = 90
⟹ m - 4, m - 2, m, m + 2, m + 4 is equal to 86, 88, 90, 92, and 94 respectively.
⟹ 2a3 = 94
⟹ a3 = $$frac{94}{2}$ = 47 Hence a1, a2, a3, a4, a5 is equal to 43, 45, 47, 49, and 51 respectively. Therefore a5 = 51 The question is "Let a1, a2, a3, a4, a5 be a sequence of five consecutive odd numbers. Consider a new sequence of five consecutive even numbers ending with 2a3. If the sum of the numbers in the new sequence is 450, then a5 is [TITA]" ##### Hence, the answer is 51 ###### 2IIM's Online CAT CoachingGet CAT Last Mile Prep Course for 799 /- Signup Now! ###### Already have an Account? ###### CAT Coaching in ChennaiCAT 2020Enroll at 44,000/- Next Weekend Batch Starts Sat, Nov 2nd, 2019 ###### Best CAT Coaching in ChennaiRegister Online, get Rs 4000/- off Attend a Demo Class ##### Where is 2IIM located? 2IIM Online CAT Coaching A Fermat Education Initiative, 58/16, Indira Gandhi Street, Kaveri Rangan Nagar, Saligramam, Chennai 600 093 ##### How to reach 2IIM? Phone:$91) 44 4505 8484
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