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Question 29 : In how many ways can 8 identical pens be distributed among Amal, Bimal, and Kamal so that Amal gets at least 1 pen, Bimal gets at least 2 pens, and Kamal gets at least 3 pens? [TITA]
Let us assume Amal gets 1 + x pens and Bimal gets 2 + y pens and Kamal gets 3 + z pens
1 + x + 2 + y + 3 + z = 8
x + y + z = 2 (x , y , z being whole numbers) or
x + (1 + y) + (3 + z )
x + y + z = 8 – 3 = 5 (x , y, z being naturals numbers)
Take 5 ones 1 _ 1 _ 1 _ 1 _ 1 , + symbol should be added in any 2 slots. (There are 4 empty slots)
This is done in 4C2 ways = 6 ways.
Alternative method is to list down the possibilities as done below.
The question is "In how many ways can 8 identical pens be distributed among Amal, Bimal, and Kamal so that Amal gets at least 1 pen, Bimal gets at least 2 pens, and Kamal gets at least 3 pens? [TITA]"
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