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Question 13: A right circular cone, of height 12 ft, stands on its base which has diameter 8 ft. The tip of the cone is cut off with a plane which is parallel to the base and 9 ft from the base. With π = \\frac{22}{7}), the volume, in cubic ft, of the remaining part of the cone is:[TITA]

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From the diagram, △OAD is similar to △OBC

So, \\frac{𝑂𝐵}{𝑂𝐴}) = \\frac{𝐵𝐶}{𝐴𝐷})

\\frac{12}{3}) = \\frac{4}{𝑟}) r = 1 ft

Volume of the remaining part = Volume of OBC – Volume OAD

Volume of the remaining part = (\\frac{1}{3}) × \\frac{22}{7}\\) × 4 × 4 × 12 ) − (\\frac{1}{3}) × \\frac{22}{7}) × 1 × 1 × 3)

Volume of the remaining part = \\frac{22}{7}) × ( 64 − 1 )

Volume of the remaining part = 198 cubic ft

The question is **"A right circular cone, of height 12 ft, stands on its base which has diameter 8 ft. The tip of the cone is cut off with a plane which is parallel to the base and 9 ft from the base. With π = \\frac{22}{7}\\), the volume, in cubic ft, of the remaining part of the cone is: [TITA]" **

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