This one is a classic question from **Mensuration**. As seen in **2IIM's CAT Blueprint**, the CAT Exam has been known to roll out at least 1 or 2 questions of this type every year and thus this topics requires your attention and extensive question solving.

For more CAT-level questions, visit ** 2IIM's CAT Question Bank.**

Question 13: A right circular cone, of height 12 ft, stands on its base which has diameter 8 ft. The tip of the cone is cut off with a plane which is parallel to the base and 9 ft from the base. With π = \\frac{22}{7}), the volume, in cubic ft, of the remaining part of the cone is:[TITA]

Try upto 40 hours for free

Learn from the best!

Limited Seats Available - Register Now!

From the diagram, △OAD is similar to △OBC

So, \\frac{𝑂𝐵}{𝑂𝐴}) = \\frac{𝐵𝐶}{𝐴𝐷})

\\frac{12}{3}) = \\frac{4}{𝑟}) r = 1 ft

Volume of the remaining part = Volume of OBC – Volume OAD

Volume of the remaining part = (\\frac{1}{3}) × \\frac{22}{7}\\) × 4 × 4 × 12 ) − (\\frac{1}{3}) × \\frac{22}{7}) × 1 × 1 × 3)

Volume of the remaining part = \\frac{22}{7}) × ( 64 − 1 )

Volume of the remaining part = 198 cubic ft

The question is **"A right circular cone, of height 12 ft, stands on its base which has diameter 8 ft. The tip of the cone is cut off with a plane which is parallel to the base and 9 ft from the base. With π = \\frac{22}{7}\\), the volume, in cubic ft, of the remaining part of the cone is: [TITA]" **

Copyrights © All Rights Reserved by 2IIM.com - A Fermat Education Initiative.

Privacy Policy | Terms & Conditions

CAT^{®} (Common Admission Test) is a registered trademark of the Indian Institutes of Management. This website is not endorsed or approved by IIMs.

2IIM Online CAT Coaching

A Fermat Education Initiative,

58/16, Indira Gandhi Street,

Kaveri Rangan Nagar, Saligramam, Chennai 600 093

**Mobile:** (91) 99626 48484 / 94459 38484

**WhatsApp:** WhatsApp Now

**Email: **info@2iim.com