CAT 2018 Question Paper | Quants Slot 1

CAT Previous Year Paper | CAT Exponents Questions | Question 25

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Question 25 :Given that x2018 y2017 = 1/2 and x2016 y2019 = 8, the value of x2 + y3 is

1. $$frac{37}{4}$ 2. $\frac{31}{4}$ 3. $\frac{35}{4}$ 4. $\frac{33}{4}$ 2IIM : Best Online CAT Coaching 2IIM's Crash Course CAT 2019 Introductory price @ 7500 Till Oct 7CAT Online Coaching Video Explanation Best CAT Coaching in Chennai CAT Coaching in Chennai - CAT 2020Starts Sat, October 5th, 2019 Explanatory Answer Method of solving this CAT Question from Exponents x2018 y2017 = $\frac{1}{2}$ ---$1)
x2016 y2019 = 8 ---(2)
Divide (1) by (2) we get ($$frac{x}{y}$)2 = $\frac{1}{16}$ y = 4x Substituting the value of y in$2)
x2016 . x2019 . 42019 = 23
x4035 . 24038 = 23
x4035 = 2-4035 => x = $$frac{1}{2}$ y = 2 x2 + y3 = $\frac{33}{4}$ The question is "Given that x2018 y2017 = 1/2 and x2016 y2019 = 8, the value of x2 + y3 is" Hence, the answer is $\frac{33}{4}$ Choice D is the correct answer. 2IIM's CAT CoursesDussehra Discount of 25% Till Oct 9CAT Online Coaching Signup Now! Already have an Account? CAT Coaching in ChennaiCAT 2020Enroll at 44,000/- Next Weekend Batch Starts Sat, Oct 5th, 2019 Best CAT Coaching in ChennaiRegister Online, get Rs 4000/- off Attend a Demo Class Where is 2IIM located? 2IIM Online CAT Coaching A Fermat Education Initiative, 10-C, Kalinga Colony, Bobbili Raja Salai K.K.Nagar, Chennai. India. Pin - 600 078 How to reach 2IIM? Phone:$91) 44 4505 8484
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