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Question 17 :Point P lies between points A and B such that the length of BP is thrice that of AP. Car 1 starts from A and moves towards B. Simultaneously, car 2 starts from B and moves towards A. Car 2 reaches P one hour after car 1 reaches P. If the speed of car 2 is half that of car 1, then the time, in minutes, taken by car 1 in reaching P from A is:[TITA]

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Let us take the distance AP = x and BP = 3x

It’s also given that Speed_{Car-2} = \\frac{1}{2}) Speed_{Car-1}

S_{1} = S S_{2} = \\frac{S}{2} )

Car 2 takes one hour more than Car 1

T_{2} = t minutes T_{2} = (t + 60) minutes

We know that Time = \\frac{Distance}{Speed})

So T_{Car-1} = \\frac{x}{S}) T_{Car-2} = \\frac{3𝑥}{\frac{S}{2}}) = \\frac{6x}{S})

T_{Car-1} = t T_{Car-2} = 6t

We know, T_{Car-2} takes (t + 60) minutes

6t = t + 60

5t = 60

t = 12 minutes

The question is **"Point P lies between points A and B such that the length of BP is thrice that of AP. Car 1 starts from A and moves towards B. Simultaneously, car 2 starts from B and moves towards A. Car 2 reaches P one hour after car 1 reaches P. If the speed of car 2 is half that of car 1, then the time, in minutes, taken by car 1 in reaching P from A is:" **

Choice C is the correct answer.

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