This very simple question from **CAT 2018 Question Paper** is based on ** Speed, Time and Distance** and combines a tinge of basic **Algebra**! These type of questions occur very often in the CAT Exam and it is needless to say that you have to master Speed, Time and Distance’s concepts to ace the exam. Give it a shot and then check out the video explanation for the same. To ace your **CAT preparation online**, solve as many questions as possible from **CAT Previous Year Paper**.

Question 4 :The distance from A to B is 60 km. Partha and Narayan start from A at the same time and move towards B. Partha takes four hours more than Narayan to reach B. Moreover, Partha reaches the mid-point of A and B two hours before Narayan reaches B. The speed of Partha, in km per hour, is

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Let Narayanan take X hrs to reach B then Partha would take X + 4 hrs

Its given that Partha reaches the mid-point of A and B two hours before Narayan reaches B

\\frac{X + 4}{2}) = X – 2 => X=8 hrs

So, Partha would take 8+4 = 12 hrs to travel 60 Kms at a speed of \\frac{60}{12}) Kmph

Speed of Partha = **5 Kmph**

The question is **"The distance from A to B is 60 km. Partha and Narayan start from A at the same time and move towards B. Partha takes four hours more than Narayan to reach B. Moreover, Partha reaches the mid-point of A and B two hours before Narayan reaches B. The speed of Partha, in km per hour, is" **

Choice D is the correct answer.

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